would I get a ticket?
Discussion in 'Experienced Truckers' Advice' started by Chewy352, Jun 29, 2015.
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That 3 feet to the midmarker light makes a huge difference.
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I think bulldog as talking about a driver talking to a shipper not a driver talking to his own company. Your point still stands though that the driver is captain of his ship. It's also key to remember that the admiral can remove the captain from said ship.
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Let me ask you this silly question.
Did the BOL say that lift only weighed 23k?
If the shipper lied about what it weighs it should be they who pay the ticket. -
If they admiral wants to remove the captain for refusing to blatantly violate DOT regs, then IMO he isn't worth working for.Chewy352 Thanks this.
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True
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Imagine how much time you save now. You're much more efficient a driver when you know how to load your wagon. Thats $$$$ in your pocket and a much easier job.
Did you get your empty axle weights? Empty wagon, full of fuel. You've found the center of the trailer to load a symmetrical load. But let's take it a step farther. You're picking up a machine, single piece 12 ft long, 52000lbs, center of gravity is 5 ft from 1 end of the machine. Can you load it evenly, and if so, how would you figure out where to put the machine on the trailer to get the drives and trailer axles even? -
Saves a ton of time especially when you load in the evening with a ton of time on your clocks only to find out you're overweight and the shipper has closed for the day. That sucks.
As for the second part give me a min orayby hours to think it through lol. -
Those are my empty weights.
To answer your question first off I would refuse the load because I can't scale more then 48,000. With my set up we try to keep loads under 47,000 lbs.
Now to answer your question seriously reducing the weight to 47,000 lbs. We are looking at 23,500 lbs on either side of the center of gravity. Putting the center of gravity on my center mark I should have 35,620 on my drives and 31,620 on my spreads.
To even them out I'm not sure how much to move the machine back from my center mark to even it out. 1 foot should equal X weight. How do I figure that out?Hurst Thanks this. -
A 48 spread axle isn't just a matter of "physical trailer center, then back x amount of distance" to "balance the load weighted heavy to the trailer axles"
You have to realize, the forward trailer axle is already moved forward, and as such will take on more weight added to the physical center of the trailer bed (assuming the axle bags are properly tuned and equalized)
Chances are, you're loading too heavy towards the trailer on many "equally distributed" loads based on what I saw in an earlier post but do it however you think best. Your "load centered" position should typically be a little behind geographic center, but probably not as much as you think.
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