wilson q?

i know they have 2 foot...
http://www.rfwiz.com/WilsonSilverLoad.htm

 

I just wanted to chime in to make sure you understand how much more difficult it is to tune electrically short antennas.

1/4 wave for 27MHz CB is about 9 feet... thus the classic 9 foot steel whip on pickup trucks with the tennis ball to prevent it from smacking the metal body.

Anything shorter begins to compromise bandwidth and there is nothing any antenna manufacturer can do to bypass this tendency without introducing lossy resistive components.

5 foot CB antennas with base loading, continuous helical loading or whatever are about the minimum length you can have before difficulties surface.

4 feet is starting to push it, but certainly doable.

Once, long ago, I met with the worst SWR challenge of my CB installation career. The owner of a long RV wanted an 18 inch CB antenna on the ladder on the back of the RV. The cabling was something like 40 feet dressed. That ladder combined with the electrically short antenna made tuning a bloody nightmare. We tried to talk the RV owner into something more sensible, but the customer is always right so we did the best we could with the limitations.

Do what you need to do, but remember bigger is better with CB antennas.

 

If all your looking to get is maybe a mile, get you one of those cell-phone look-a-like CB Antenna's that stick on the window...They are about a foot tall, and you will be hearing and transmitting "almost" a mile in either direction! Or, get a GI Joe walkie-talkie...I think they might get out little over a mile...

 

Heres the formula for finding Q, since you ask....

1. ax[SUP]2[/SUP] + bx + c = 0, s x = –0.58, x = 2.58, rounded to two decimal places.
   Warning: The "solution" or "roots" or "zeroes" of a quadratic are usually required to be in the "exact" form of the answer. In the example above, the exact form is the one with the square roots of ten in it. You'll need to get a calculator approximation in order to graph the x-intercepts or to simplify the final answer in a word problem. But unless you have a good reason to think that the answer is supposed to be a rounded answer, always go with the exact form.
   [TABLE="width: 583"]
   [TR]
   [TD="width: 367"]Compare the solutions of 2x[SUP]2[/SUP] – 4x – 3 = 0
   
   
   Completing the square
   
   
   ​
   
   1. Divide each side by a, the coefficient of the squared term.
   2. Rearrange the equation so that the constant term c/a is on the right side.
   3. Add the square of one-half of b/a, the coefficient of x, to both sides. This "completes the square", converting the left side into a perfect square.
   4. Write the left side as a square and simplify the right side if necessary.
   5. Produce two linear equations by equating the square root of the left side with the positive and negative square roots of the right side.
   6. Solve the two linear equations.
   We illustrate use of this algorithm by solving 2x[SUP]2[/SUP] + 4x − 4 = 0
   
   
   
   [/TD]
   [/TR]
   [/TABLE]