Have a question for you guys.
A while back I think it was @Heavy Hammer talked about this very thing.
Darned if I can find it now. Looked online and even broke out the math books with no luck.
Here is my riddle. How do you calculate the weight that will be placed on the front / rear axle groups of a trailer according to the center of gravity of the load, verses the center of the trailers balance point?
Obviously if it is centered it will be equal. And if it is forward or rear of center it will be more or less.
Is there an equation to figure out what the actual weights will be in relation to the trailers balance point?
Lets say you need to crane load a piece of equipment. Load is 70,000#, 30' long and it is evenly balanced. You will be at max weight on all your axle groups. Has to be placed on the trailer exactly. The distance between your kingpin and the center of your trailer group is 41'. You need to put 25,000# on the front and 45,000# on the rear of the trailer.
How far to the rear of center on the trailer do you place the center of the load, and how did you calculate it?
Any way to know for sure without looking like a monkey fornicating a football while watching air gauges?
Math formula for load placement
Discussion in 'Heavy Haul Trucking Forum' started by old iron, Feb 13, 2016.
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No expert but...
(25,000/45,000)41 = 22.7777777
So, 22.8' from the kingpin would be the center of the load.
Right? Wrong? -
For the center of a 48 foot trailer that would be about right. According the math that was posted from kingpin to center of spread axle. And would only work if the weights were ideal. (split evenly )
He wants 20,000 more on the rears. The load would have to be farther back. Or the weight of the load.
And when you think about it. The trailer always gets most of the weight anyways. The axles only weigh around 9,000 while the drives weigh closer to 19,500. On my setup anyways.A perfectly balanced load around the middle of the trailer. All axles weigh the same. The trailer is still packing 10,000 more pounds over the drives.
Watching the truck gauges is all i've ever done. Trailer gauges too if available.
Good question. I'll be watching for that new math to be posted. -
To me the honest answer would be, experience and trial and error. It's every bit as much art as it is science. You'll just have to get some loads and figure it out, every truck and trailer is a little different.
old iron Thanks this. -
Tallest trailers has an awesome calculator on their website. You need to input lots of weights and measurements into it to get it accurate. In your scenario tho you forgot how much weight of the load is going to transfer to your steer so if you want 25k on the drives you need to add the transfer into that number.
old iron Thanks this. -
Here is the Talbert calculator.
http://www.talbertmfg.com/custompage.asp?pg=widetemplateold iron Thanks this. -
You would need to have your empty weights to start. That load would be maxing a 6 axle rig. Center of trailer is halfway between the kingpin and the middle trailer axle.
30ft long, 70000lbs. 70000/12=5833.33. Dead center would put 35000 per axle group. So to put 45000 on the trailer axles, place it 1'9 towards the rear.
The problem that I see is the trailer used. Haven't seen a 6 axle rig with a 34 ft well.old iron Thanks this. -
mpd240, old iron, TripleSix and 1 other person Thank this.
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johndeere4020 Thanks this.
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