Both trucks will perform the same on a hill only time that 3.90 will be better than 3.70 is when you’re pulling over 80,000 on a 6% or greater grade the 3.90 might stay on the topside of the box while the 3.70 will need basement gears .
3.70 vs 3.90, what is the difference?
Discussion in 'Ask An Owner Operator' started by Thotphobia, Aug 23, 2021.
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Thanks guys for all the replies! Sorry for not adding the extra info. I live in NC and I pull logs. Average weight for me is 83k. No hills where I am. Straight out flat land with 24.5s. And I usually never get on the interstate roads. Just back roads
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I would even venture into 4.10s, fuel mileage is not a concern heavy/off-road, getting moving without blowing the drive train is. Especially on tall 24s
w9l, ProfessionalNoticer, Oxbow and 4 others Thank this. -
Difference is 5.2% So with 3.70 at hundred mph at a given rpm the 3.90 at same rpm would be around 95. So if you are only going 50 at a given rpm with 3.70 the 3.90 at same rpm would be around 47-48mph.
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Take the 3.90 then……
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Did anyone consider engine torque ratings or transmission final drive ratios. I know he asks about identical set ups. Still more torque plays a lot into climbing a hill, without dropping gears. Since he’s on flat ground, I’d think the 3.70s would yield better fuel economy. If he’s got enough torque, power difference would be less noticeable. Technically the 3.70 would be faster top speed. And with enough torque faster from a dead stop, due to longer legs in each gear.
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Neither. I'd go with 4.10s if I were you. In fact, I'm getting ready to switch everything over to them myself and I run mostly paved state highways and interstates with occasional job site deliveries. 13 speed and tall 24s with a 925 CAT. 1600 RPM is 70 MPH.
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