In this chapter, we provide RS Aggarwal Solutions for Class 10 Chapter 3 Linear equations in two variables EX 3C Maths for English medium students, Which will very helpful for every student in their exams. Students can download the latest RS Aggarwal Solutions for Class 10 Chapter 3 Linear equations in two variables EX 3C Maths pdf, free RS Aggarwal Solutions Class 10 Chapter 3 Linear equations in two variables EX 3C Maths book pdf download. Now you will get step by step solution to each question.

Textbook | NCERT |

Class | Class 10 |

Subject | Maths |

Chapter | Chapter 3 |

Chapter Name | Linear equations in two variables |

Exercise | 3 C |

Category | RS Aggarwal Solutions |

**RS Aggarwal Solutions Class 10 Chapter 3 Linear equations in two variables Ex 3C**

**Question 1:**

x + 2y + 1 = 0 —(1)

2x – 3y – 12 = 0 —(2)

By cross multiplication, we have

Hence, x = 3 and y = -2 is the solution**Question 2:**

2x + 5y – 1 = 0 —(1)

2x + 3y – 3 = 0 —(2)

By cross multiplication we have

Hence the solution is x = 3, y = -1**Question 3:**

3x – 2y + 3 = 0

4x + 3y – 47 = 0

By cross multiplication we have

Hence the solution is x = 5, y = 9**Question 4:**

6x – 5y – 16 = 0

7x – 13y + 10 = 0

By cross multiplication we have

Hence the solution is x = 6, y = 4**Question 5:**

3x + 2y + 25 = 0

2x + y + 10 = 0

By cross multiplication, we have

Hence the solution is x = 5, y = -20**Question 6:**

2x + y – 35 = 0

3x + 4y – 65 = 0

By cross multiplication, we have

**Question 7:**

7x – 2y – 3 = 0

By cross multiplication, we have

Hence x = 1, y = 2 is the solution**Question 8:**

**Question 9:**

ax + by – (a – b) = 0

bx – ay – (a + b) = 0

By cross multiplication, we have

**Question 10:**

2ax + 3by – (a + 2b) = 0

3ax + 2by – (2a + b) = 0

By cross multiplication, we have

**Question 11:**

By cross multiplication, we have

**Question 12:**

By cross multiplication, we have

**Question 13:**

By cross multiplication we have

**Question 14:**

Taking

u + v – 7 = 0

2u + 3v – 17 = 0

By cross multiplication, we have

Hence the solution is

**Question 15:**

Let

in the equation

5u – 2v + 1 = 0

15u + 7v – 10 = 0

**Question 16:**

**All Chapter RS Aggarwal Solutions For Class 10 Maths**

—————————————————————————–**All Subject NCERT Exemplar Problems Solutions For Class10**

**All Subject NCERT Solutions For Class 10**

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