Example 17 - Chapter 6 Class 11 Linear Inequalities (Term 2)
Last updated at Dec. 8, 2016 by Teachoo
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Example 17 Solve 5 5 3 2 8. 5 5 3 2 8 Multiplying 2 all sides (Eliminating 2) 5 2 5 3x 8 2 10 5 3x 16 Subtracting 5 all sides (Eliminating 5) 10 5 5 3x 5 16 5 10 5 5 3x 5 16 5 15 3x 11 Dividing 3 all sides (Eliminating 3) 15 3 3 3 11 3 -5 11 3 Since x is negative, we multiply both sides by -1 & change the signs ( 1) (-5) ( 1) ( x) ( 1) ( 11 3 ) 5 x 11 3 11 3 x 5 Thus, x is a real number which is less than or equal to 5 and greater than or equal to 11 3 Hence, x , 5 is the solution
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