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Sand Load Formula (Rail Car)

Discussion in 'Oilfield Trucking Forum' started by Highway Hypnosis, Mar 27, 2017.

  1. Mar 27, 2017 #1
    Highway Hypnosis

    Highway Hypnosis Light Load Member

    144
    135
    Apr 12, 2014
    Minot, ND
    0
    Scenario: Company driver assigned new equipment & is unfamiliar with trailer load suspension.

    Strategy: Load light on the first attempt; load exact on the second attempt.

    Example: First pass at 45psi trailer load suspension scaled out at 36,000 lbs.

    45 = PSI = 48 psi needed for a full load.
    36 = 40

    Calculator Entry: 45 x 40 ÷ 36 = 48

    Haven't tried this... just woke up, had a cig & thought all of this crazy **** up. Will give it a try at some point.
     
    Last edited: Mar 27, 2017
    Highway Hypnosis, Mar 27, 2017
    Highway Hypnosis, Mar 27, 2017
    #1
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  3. Mar 31, 2017 #2
    RockinChair

    RockinChair Road Train Member

    5,250
    13,618
    Feb 19, 2012
    Lubbock, TX & thereabouts
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    I'm not a math whiz, but 45/36 = 5/4. Therefore, I assume X/40 should be 50/40.
     
    RockinChair, Mar 31, 2017
    RockinChair, Mar 31, 2017
    #2
    not4hire Thanks this.
  4. Mar 31, 2017 #3
    not4hire

    not4hire Road Train Member

    7,142
    26,957
    May 16, 2012
    Calgary
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    45 x 40 ÷ 36 = 50

    Another way is how many lbs per psi?
    36,000 ÷ 45 = 800
    40,000 ÷ 800 = 50 (assuming equal and level loading)
     
    not4hire, Mar 31, 2017
    not4hire, Mar 31, 2017
    #3
    RockinChair and Highway Hypnosis Thank this.
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