So I was put OOS today...

Yeah, that sinks.

 

Not entirely. Pretty sure you can do it as long as the chain is loose in between. One example is mini excavators I haul, the tiedowns are a foot from the rub rail on the outside of the track. I actually don't use the hooks on the chain, instead I loop the chain around the spool and through the securement point, and use the binder to pull the other side. Like a big loop. I don't see an issue doing that, and I've done it many times.

Code:

                     \ /
                     .|.
                    ./.\
                   . B .
                  . B   H
                 . B
                . B
               . B..............................(Loose chain)................
RRRRRRRRRRRRRR.S.RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
              .

I hope that explains it, and the chain does the same thing on the other side pulling the other way. The hook is completely loose. So is the chain in the middle. That's the key or it's considered one point even though you have two binders.

What you can't do is similar to the picture above. Instead of taking the binder to the rub rail (which has to he rated for a WLL to be legal) simply just use it on the chain only a little further up, and make that middle slop disappear. That's no different than putting one in the middle underneath which is what got our fellow driver in trouble.

 

Did my other post dissappear? The troopers math is wrong, it's 1225 not 1229.

You're actually making two fatal mistakes here. First you're adding up every securement device. You can't do that. You have to consider anchor points. The math works as follows:

50% of 11850 = 5925 aggregate required

securement points WLL are the lesser of all your securement devices. In this case it is your 5/16 chain which is 4700 lbs. That extra 700 of your binders is wasted. Always use the LOWEST number of your system.

But here's the problem, you're using the direct method (half of WLL) AND you only have TWO securement points total! It doesn't matter that your securement point is 6-7 feet long. It's still only ONE securement point. How many times does the chain loop under your spools? Once on each side!

4700 / 2 = 2350 for direct tie down

2350 per tiedown 2 tiedowns = 4700 aggregate

5925 - 4700 = 1225 short

When you added the 2 binders you created 2 more securement points and doubled your aggregate.

 

I wouldnt do flatbed even for $100,000 per year.

 

Xactly. Not when I can make more than 3/4 of that swinging doors.

 

kona911, what most of these folks don't know or have forget is there are exceptions to the tie downs requirements that can be specified by shippers on items that can be damaged by oversecrement.

you haven't mentioned where you loaded in this post, but I would put good money on yoork a/c in norman, Oklahoma. you have the load secured just as is required as to not damage the load. as long as you got those pictures , and that's where you loaded, safety isn't going to give you a problem. you loaded it just as the shipper has required and every load leaving there is don't with those units that require chains. so don't sweat the safety guy, you did as we do on every load out of there.

in fact I almost bet they will help on the data q on this incident. its like the escalators we haul 48 feet long and two chains, one on each end, shoots the 10 foot rule in the head

 

wrong , just wrong

 

But just think of all the extra sweat pants, crocs and fingerless gloves you can buy with that other 1/4. Not to mention all the extra time you'll have to sit at the lunch counter because you are not sitting at a dock for 6 hours a day.

Thank you ... Please stick to swinging doors. We appreciate it

 

If that's all you are making, you're doing it wrong anyways.